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# 17. Find Pair Given Difference

The problem can be found at the following link: [Question Link](https://www.geeksforgeeks.org/problems/find-pair-given-difference1559/1)

## My Approach

* The input array arr is sorted to facilitate the two-pointer technique.
* Use two pointers low and high. Initialize low to 0 and high to 1.
* Use a while loop to traverse the array with the condition low < n and high < n.
* If the absolute difference between the elements at high and low is equal to x, return 1 (indicating a pair is found).
* If the absolute difference is less than x, increment the high pointer to increase the difference.
* If the absolute difference is greater than x, increment the low pointer to decrease the difference.
* If no such pair is found by the end of the loop, return -1.

## Time and Auxiliary Space Complexity

* **Time Complexity**: The time complexity of this approach is `O(NlogN)`, where N is the number of elements in the array.
* **Auxiliary Space Complexity**: The auxiliary space complexity is `O(1)`.

## Code (C++)

```cpp
class Solution {
  public:
    int findPair(int n, int x, vector<int> &arr)
    {
        sort(arr.begin(), arr.end());
        int low=0, high=1;
        while (low<n && high<n)
        {
            if (abs(arr[high]-arr[low])==x)
                return 1;
            else if (abs(arr[high]-arr[low])<x)
                high++;
            else low++;
        }
        return -1;
    }
};
```

## Contribution and Support

For discussions, questions, or doubts related to this solution, please visit our [discussion section](https://github.com/getlost01/gfg-potd/discussions). We welcome your input and aim to foster a collaborative learning environment.

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