24. Right View of Binary Tree
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To get the right view of a binary tree, we perform a level order traversal (BFS) and keep track of the last node encountered at each level. The rightmost node at each level will be included in the result vector.
Perform a level order traversal (BFS) using a queue named q
. Start by inserting the root
node into the queue.
While the queue is not empty, repeat the following steps:
Iterate through all the nodes at the current level (the number of nodes currently in the queue, denoted by sz
):
Dequeue the front node from the queue and assign it to the variable last
.
If last
has a left child, enqueue it into the queue.
If last
has a right child, enqueue it into the queue.
Once all nodes at the current level have been traversed, record the value of last->data
in the out
vector.
Time Complexity: O(N)
, where N
is the number of nodes in the binary tree.
Auxiliary Space Complexity: O(W)
, where W
is the maximum width of the binary tree (number of nodes in the level with the most nodes).
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