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The problem can be found at the following link:
To check if two strings, s1
and s2
, are rotations of each other,
I concatenate s1
with itself to create a new string s
.
Then, I check if s2
is a substring of s
using the find
function. If the index is not -1, then s2
is a rotation of s1
.
Time Complexity: O(N)
, where N
is the length of s1
.
Auxiliary Space Complexity: O(N)
, as we create a new string by concatenation.
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