09. Check for Children Sum Property in a Binary Tree
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The problem can be found at the following link:
Base Cases:
If the root is NULL, return 1.
If the root is a leaf, return 1.
Calculate Left and Right Sums:
Initialize leftSum and rightSum to 0.
If the left child exists, set leftSum to its data.
If the right child exists, set rightSum to its data.
Check Sum Property:
Check if the data of the current node equals the sum of leftSum and rightSum.
Recursively check the sum property for the left and right subtrees.
Return 1 if all conditions are met; otherwise, return 0.
Time Complexity: The time complexity of this solution is O(N)
, where N
is the number of nodes in the binary tree.
Auxiliary Space Complexity: The auxiliary space complexity is O(H)
, where H
is the height of the binary tree.
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